I have an array in the following format.

const arr = [{name:'11'},{name:'10'},{name:'9'},{name:'8'},{name:'7'}
{name:'6'},{name:'5'},{name:'4'},{name:'3'},{name:'2'},{name:'1'}
{name:'UN'},{name:'PG'},{name:'LN'},
{name:'12'},{name:'13'}]

I can sort it to get an output like below.

arr.sort((x, y)=> {
        if(x.name == 'LN' || x.name=='UN' || x.name== 'PG' || (parseInt(x.name)<parseInt(y.name))) {
          return -1;
        }
        return 0;
      })

Current Output : simplified for easy visualization

[LN,PG,UN,1,2,3,4,5,6,7,8,9,10,11,12,13]

I want PG to come after UN. Should do a swap like below after sorting or can it be done in the sort function it self?

[arr[1], arr[2]] = [arr[2],arr[1]]

Expected Output : simplified for easy visualization

[LN,UN,PG,1,2,3,4,5,6,7,8,9,10,11,12,13]

>Solution :

One way is to give the name a rank,

Assuming your numbers are always positive, a really simple way to rank is use a lookup for the text, making them less than 0. If new name types appear in the future it’s just a case of updating the rank lookup. You can then sort on this rank function.

eg..

const arr = [{name:'11'},{name:'10'},{name:'9'},{name:'8'},{name:'7'},
{name:'6'},{name:'5'},{name:'4'},{name:'3'},{name:'2'},{name:'1'},
{name:'UN'},{name:'PG'},{name:'LN'},
{name:'12'},{name:'13'}];

const ranks = {
  LN: -3,
  UN: -2,
  PG: -1
}

function rank(n) {
  if (ranks[n]) return ranks[n]
  else return Number(n);
}

arr.sort((a,b) => {
  return rank(a.name) - rank(b.name);
});

console.log(arr);