How to find missing hours and show data as 0

This query pulls counts for every hour of every day but leaves off any days and hours that don’t have counts. How can I fill in the missing dates and hours between the dates selected with 0 for the counts?

SELECT CAST(RecordTime AS date) AS Date, DATENAME(dw, RecordTime) AS [Day of the week], DATEPART(hour, RecordTime) AS [Hour of the day], COUNT(*) AS [Hourly Count]
    FROM Counts
    WHERE (RecordTime >= CONVERT(DATETIME, '2022-04-01 00:00:00', 102)) AND (RecordTime < CONVERT(DATETIME, '2022-05-01 00:00:00', 102)) AND (MachineNum = 11) AND (Cavity = 1)
    GROUP BY CAST(RecordTime AS date), DATEPART(hour, RecordTime), DATENAME(dw, RecordTime)
    ORDER BY Date, [Hour of the day]

>Solution :

As Larnu suggested, you need to generate a full dataset with all day+hour combinations in the range, in order to left join to. By my calculation you need 30 days * 24 hours = 720 rows. If you don’t already have a numbers table, or a calendar table, or a sequence generating function, you can generate this using recursive CTEs as follows:

DECLARE @StartDate     datetime = '20220401',
        @AfterLastDate datetime = '20220501';
        
;WITH days(d) AS
(
  SELECT 0 UNION ALL SELECT d+1 FROM days
  WHERE d < DATEDIFF(DAY, @StartDate, @AfterLastDate) - 1
), hours(h) AS
(
  SELECT 0 UNION ALL SELECT h+1 FROM hours WHERE h<23
),
dates(DayHour, h) AS
(
  SELECT DATEADD(HOUR, hours.h, DATEADD(DAY, days.d, @StartDate)), hours.h
  FROM days CROSS JOIN hours
)
SELECT d.DayHour, DATENAME(WEEKDAY, DayHour), d.h
  FROM dates AS d
  ORDER BY d.DayHour;

Output:

DayHour	Day of the week	Hour of the day
2022-04-01 00:00:00.000	Friday	0
2022-04-01 01:00:00.000	Friday	1
2022-04-01 02:00:00.000	Friday	2
… 714 more rows …
2022-04-30 21:00:00.000	Saturday	21
2022-04-30 22:00:00.000	Saturday	22
2022-04-30 23:00:00.000	Saturday	23

• Example db<>fiddle

Now, we just need to left outer join that against your existing table:

DECLARE @StartDate     datetime = '20220401',
        @AfterLastDate datetime = '20220501';
        
;WITH days(d) AS
(
  SELECT 0 UNION ALL SELECT d+1 FROM days
  WHERE d < DATEDIFF(DAY, @StartDate, @AfterLastDate) - 1
), hours(h) AS
(
  SELECT 0 UNION ALL SELECT h+1 FROM hours WHERE h<23
),
dates(DayHour, h) AS
(
  SELECT DATEADD(HOUR, hours.h, DATEADD(DAY, days.d, @StartDate)), 
    hours.h FROM days CROSS JOIN hours
)
SELECT [Date] = CONVERT(date, d.DayHour), 
  [Day of the week] = DATENAME(WEEKDAY, d.DayHour), 
  [Hour of the day] = d.h,
  [Hourly Count] = COUNT(c.RecordTime)
FROM dates AS d
LEFT OUTER JOIN dbo.Counts AS c
ON c.RecordTime >= d.DayHour
  AND c.RecordTime < DATEADD(HOUR, 1, d.DayHour)
  AND c.MachineNum = 11
  AND c.Cavity = 1
GROUP BY CONVERT(date, d.DayHour), DATENAME(WEEKDAY, DayHour), d.h
ORDER BY [Date], [Hour of the day];

• Example db<>fiddle